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    ∴ y>0. 查看更多

     

    題目列表(包括答案和解析)

    設(shè),對(duì)任意實(shí)數(shù)t,記
    (I)求函數(shù)y=f(x)-g8(x)的單調(diào)區(qū)間;
    (II)求證:(ⅰ)當(dāng)x>0時(shí),f(x)≥gt(x)對(duì)任意正實(shí)數(shù)t成立;
    (ⅱ)有且僅有一個(gè)正實(shí)數(shù)x,使得g8(x)≥gt(x)對(duì)任意正實(shí)數(shù)t成立.

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    設(shè),對(duì)任意實(shí)數(shù)t,記

    (Ⅰ)求函數(shù)y=f(x)-g2(x)的單調(diào)區(qū)間;

    (Ⅱ)求證:(ⅰ)當(dāng)x>0時(shí),f(x)gf(x)≥g2(x)對(duì)任意正實(shí)數(shù)t成立;

    (Ⅲ)有且僅有一個(gè)正實(shí)數(shù)x0,使得gx(x0)≥gt(x0)對(duì)任意正實(shí)數(shù)t成立.

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    設(shè)f(x)=
    x3
    3
    ,對(duì)任意實(shí)數(shù)t,記gt(x)=t
    2
    3
    x-
    2
    3
    t

    (Ⅰ)求函數(shù)y=f(x)-g8(x)的單調(diào)區(qū)間;
    (Ⅱ)求證:(。┊(dāng)x>0時(shí),f(x)≥gt(x)對(duì)任意正實(shí)數(shù)t成立;
    (ⅱ)有且僅有一個(gè)正實(shí)數(shù)x0,使得g8(x0)≥gt(x0)對(duì)任意正實(shí)數(shù)t成立.

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    設(shè)f(x)=
    x3
    3
    ,對(duì)任意實(shí)數(shù)t,記gt(x)=t
    2
    3
    x-
    2
    3
    t

    (I)求函數(shù)y=f(x)-g8(x)的單調(diào)區(qū)間;
    (II)求證:(ⅰ)當(dāng)x>0時(shí),f(x)≥gt(x)對(duì)任意正實(shí)數(shù)t成立;
    (ⅱ)有且僅有一個(gè)正實(shí)數(shù)x0,使得g8(x0)≥gt(x0)對(duì)任意正實(shí)數(shù)t成立.

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    設(shè)f(x)=,對(duì)任意實(shí)數(shù)t,記gt(x)=x-t.

    (Ⅰ)求函數(shù)y=f(x)-g8(x)的單調(diào)區(qū)間;

    (Ⅱ)求證:(1)當(dāng)x>0時(shí),f(x)≥gt(x)對(duì)任意正實(shí)數(shù)t成立;

    (2)有且僅有一個(gè)正實(shí)數(shù)x0,使得g8(x0)≥gt(x0)對(duì)任意正實(shí)數(shù)t成立.

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